在Python中将CSV转换为UTF-8

UnicodeDecodeError: 'utf-8' codec can't decode byte 0xa0 in position 1895: invalid start byte.

我已经阅读了Unicode和UTF-8编码的python CSV documentation并实现了它.
但是,我的输出文件生成时没有数据.不知道我在这里做错了什么.

import csv

path =  '/Users/johndoe/file.csv'

with open(path, 'r') as infile, open(path + 'final.csv', 'w') as outfile:

    def unicode_csv(infile, outfile):
        inputs = csv.reader(utf_8_encoder(infile))
        output = csv.writer(outfile)

        for index, row in enumerate(inputs):
            yield [unicode(cell, 'utf-8') for cell in row]
            if index == 0:
                 continue
        output.writerow(row)

    def utf_8_encoder(infile):
        for line in infile:
            yield line.encode('utf-8')

unicode_csv(infile, outfile)

with open(path, 'r') as infile:

这两个参数是encoding =’UTF-8’和errors =’ignore’.这允许我创建一个原始CSV的副本,没有标题,也没有UnicodeDecodeError.以下是完成的代码.

import csv

path =  '/Users/johndoe/file.csv'

with open(path, 'r', encoding='utf-8', errors='ignore') as infile, open(path + 'final.csv', 'w') as outfile:
     inputs = csv.reader(infile)
     output = csv.writer(outfile)

     for index, row in enumerate(inputs):
         # Create file with no header
         if index == 0:
             continue
         output.writerow(row)